[Free] 2017(July) EnsurePass Examcollection Cisco 200-125 Dumps with VCE and PDF 21-30

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CCNA Cisco Certified Network Associate CCNA (v3.0)

Question No: 21 – (Topic 1)

In an Ethernet network, under what two scenarios can devices transmit? (Choose two.)

  1. when they receive a special token

  2. when there is a carrier

  3. when they detect no other devices are sending

  4. when the medium is idle

  5. when the server grants access

Answer: C,D Explanation:

Ethernet network is a shared environment so all devices have the right to access to the medium. If more than one device transmits simultaneously, the signals collide and cannot reach the destination.

If a device detects another device is sending, it will wait for a specified amount of time before attempting to transmit.

When there is no traffic detected, a device will transmit its message. While this transmission is occurring, the device continues to listen for traffic or collisions on the LAN. After the message is sent, the device returns to its default listening mode.

Question No: 22 – (Topic 1)

Host 1 is trying to communicate with Host 2. The e0 interface on Router C is down.


Which of the following are true? (Choose two.)

  1. Router C will use ICMP to inform Host 1 that Host 2 cannot be reached.

  2. Router C will use ICMP to inform Router B that Host 2 cannot be reached.

  3. Router C will use ICMP to inform Host 1, Router A, and Router B that Host 2 cannot be reached.

  4. Router C will send a Destination Unreachable message type.

  5. Router C will send a Router Selection message type.

  6. Router C will send a Source Quench message type.

Answer: A,D Explanation:

Host 1 is trying to communicate with Host 2. The e0 interface on Router C is down. Router C will send ICMP packets to inform Host 1 that Host 2 cannot be reached.

Question No: 23 – (Topic 1)

Refer to the exhibit.


After HostA pings HostB, which entry will be in the ARP cache of HostA to support this transmission?


  1. Exhibit A

  2. Exhibit B

  3. Exhibit C

  4. Exhibit D

  5. Exhibit E

  6. Exhibit F

Answer: A Explanation:

Host A knows host B is in another network so it will send the pings to its default gateway Host A sends a broadcast frame asking the MAC address of This information (IP and MAC address of the default gateway) is saved in its ARP cache for later use.

Question No: 24 – (Topic 1)

Refer to the exhibit.


What two results would occur if the hub were to be replaced with a switch that is configured with one Ethernet VLAN? (Choose two.)

  1. The number of collision domains would remain the same.

  2. The number of collision domains would decrease.

  3. The number of collision domains would increase.

  4. The number of broadcast domains would remain the same.

  5. The number of broadcast domains would decrease.

  6. The number of broadcast domains would increase.

Answer: C,D Explanation:

Basically, a collision domain is a network segment that allows normal network traffic to flow back and forth. In the old days of hubs, this meant you had a lot of collisions, and the old CSMA/CD would be working overtime to try to get those packets re-sent every time there was a collision on the wire (since Ethernet allows only one host to be transmitting at once without there being a traffic jam). With switches, you break up collision domains by switching packets bound for other collision domains. These days, since we mostly use switches to connect computers to the network, you generally have one collision domain to a PC.

Broadcast domains are exactly what they imply: they are network segments that allow broadcasts to be sent across them. Since switches and bridges allow for broadcast traffic to go unswitched, broadcasts can traverse collision domains freely. Routers, however, don#39;t allow broadcasts through by default, so when a broadcast hits a router (or the perimeter of a VLAN), it doesn#39;t get forwarded. The simple way to look at it is this way: switches break up collision domains, while routers (and VLANs) break up collision domains and broadcast domains. Also, a broadcast domain can contain multiple collision domains, but a collision domain can never have more than one broadcast domain associated with it.

Collision Domain: A group of Ethernet or Fast Ethernet devices in a CSMA/CD LAN that are connected by repeaters and compete for access on the network. Only one device in the collision domain may transmit at any one time, and the other devices in the domain listen to the network in order to avoid data collisions. A collision domain is sometimes referred to as an Ethernet segment.

Broadcast Domain: Broadcasting sends a message to everyone on the local network (subnet). An example for Broadcasting would be DHCP Request from a Client PC. The Client is asking for a IP Address, but the client does not know how to reach the DHCP Server. So the client sends a DHCP Discover packet to EVERY PC in the local subnet (Broadcast). But only the DHCP Server will answer to the Request.

How to count them? Broadcast Domain:

No matter how many hosts or devices are connected together, if they are connected with a repeater, hub, switch or bridge, all these devices are in ONE Broadcast domain (assuming a single VLAN). A Router is used to separate Broadcast-Domains (we could also call them Subnets – or call them VLANs).

So, if a router stands between all these devices, we have TWO broadcast domains.

Collision Domain:

Each connection from a single PC to a Layer 2 switch is ONE Collision domain. For example, if 5 PCs are connected with separate cables to a switch, we have 5 Collision domains. If this switch is connected to another switch or a router, we have one collision domain more.

If 5 Devices are connected to a Hub, this is ONE Collision Domain. Each device that is connected to a Layer 1 device (repeater, hub) will reside in ONE single collision domain.

Question No: 25 – (Topic 1)

Refer to the exhibit.


Host A pings interface S0/0 on router 3. What is the TTL value for that ping?

A. 252

B. 253

C. 254

D. 255

Answer: B Explanation:

From the CCNA ICND2 Exam book: 鈥淩outers decrement the TTL by 1 every time they forward a packet; if a router decrements the TTL to 0, it throws away the packet. This prevents packets from rotating forever.鈥?I want to make it clear that before the router forwards a packet, the TTL is still remain the same. For example in the topology above, pings to S0/1 and S0/0 of Router 2 have the same TTL.

The picture below shows TTL values for each interface of each router and for Host B. Notice that Host A initializes ICMP packet with a TTL of 255:


Question No: 26 – (Topic 1)

Refer to the exhibit.


Which three statements correctly describe Network Device A? (Choose three.)

  1. With a network wide mask of, each interface does not require an IP address.

  2. With a network wide mask of, each interface does require an IP address on a unique IP subnet.

  3. With a network wide mask of, must be a Layer 2 device for the PCs to communicate with each other.

  4. With a network wide mask of, must be a Layer 3 device for the PCs to communicate with each other.

  5. With a network wide mask of, each interface does not require an IP address.

Answer: B,D,E Explanation:

If Subnet Mask is the hosts vary from x.x.x.0 – x.x.x.127 amp; x.x.x.128- x.x.x.255, so the IP Addresses of 2 hosts fall in different subnets so each interface needs an IP an address so that they can communicate each other.

If Subnet Mask is the 2 specified hosts fall in different subnets so they need a Layer 3 device to communicate.

If Subnet Mask is the 2 specified hosts are in same subnet so are in network address and can be accommodated in same Layer 2 domain and can communicate with each other directly using the Layer 2 address.

Question No: 27 DRAG DROP – (Topic 1)

Refer to the exhibit. PC_1 is sending packets to the FTP server. Consider the packets as they leave RouterA interface Fa0/0 towards RouterB. Drag the correct frame and packet address to their place in the table.




Topic 2, LAN Switching Technologies

Question No: 28 – (Topic 2)

Refer to the exhibit.


A network technician is asked to design a small network with redundancy. The exhibit represents this design, with all hosts configured in the same VLAN. What conclusions can be made about this design?

  1. This design will function as intended.

  2. Spanning-tree will need to be used.

  3. The router will not accept the addressing scheme.

  4. The connection between switches should be a trunk.

  5. The router interfaces must be encapsulated with the 802.1Q protocol.

Answer: C Explanation:

Each interface on a router must be in a different network. If two interfaces are in the same network, the router will not accept it and show error when the administrator assigns it.

Question No: 29 – (Topic 2)

Which two of these statements regarding RSTP are correct? (Choose two.)

  1. RSTP cannot operate with PVST .

  2. RSTP defines new port roles.

  3. RSTP defines no new port states.

  4. RSTP is a proprietary implementation of IEEE 802.1D STP.

  5. RSTP is compatible with the original IEEE 802.1D STP.

Answer: B,E Explanation:

When network topology changes, rapid spanning tree protocol (IEEE802.1W, referred to as RSTP) will speed up significantly the speed to re-calculate spanning tree. RSTP not only defines the role of other ports: alternative port and backup port, but also defines status of 3 ports: discarding status, learning status, forwarding status.

RSTP is 802.1D standard evolution, not revolution. It retains most of the parameters, and makes no changes.

Question No: 30 – (Topic 2)

Three switches are connected to one another via trunk ports. Assuming the default switch configuration, which switch is elected as the root bridge for the spanning-tree instance of VLAN 1?

  1. the switch with the highest MAC address

  2. the switch with the lowest MAC address

  3. the switch with the highest IP address

  4. the switch with the lowest IP address

Answer: B Explanation:

Each switch in your network will have a Bridge ID Priority value, more commonly referred to as a BID. This BID is a combination of a default priority value and the switch#39;s MAC address, with the priority value listed first. The lowest BID will win the election process.

For example, if a Cisco switch has the default priority value of 32,768 and a MAC address

of 11-22-33-44-55-66, the BID would be 32768:11-22-33-44-55-66. Therefore, if the switch priority is left at the default, the MAC address is the deciding factor in the root bridge election.

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